Submission #325636

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Source Code Expand

#include <iostream>
#include <string>

typedef long long LL;
using namespace std;

int main() {
	string s; cin >> s;
	s += "$$";
	int n = s.length();
	LL ret = 0;
	for (int i = 0; s[i];) {
		int j;
		for (j = i; s[j] == '2' && s[j+1] == '5'; j += 2);
		LL t = (j - i) / 2;
		ret += t * (t + 1) / 2;
		i = j + 1;
	}
	cout << ret << endl;
	return 0;
}

Submission Info

Judge Result